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2x^2+5x^2=3364
We move all terms to the left:
2x^2+5x^2-(3364)=0
We add all the numbers together, and all the variables
7x^2-3364=0
a = 7; b = 0; c = -3364;
Δ = b2-4ac
Δ = 02-4·7·(-3364)
Δ = 94192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{94192}=\sqrt{13456*7}=\sqrt{13456}*\sqrt{7}=116\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-116\sqrt{7}}{2*7}=\frac{0-116\sqrt{7}}{14} =-\frac{116\sqrt{7}}{14} =-\frac{58\sqrt{7}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+116\sqrt{7}}{2*7}=\frac{0+116\sqrt{7}}{14} =\frac{116\sqrt{7}}{14} =\frac{58\sqrt{7}}{7} $
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